To find the base-10 equivalencies "s" spaces to the right of the decimal, in base system B:
(B-n)*B^(-s) where n-values range from n=1 to n=(b-1)
I'm only certain that this works for b=2 b=3 b=4 b=5 b=6 b=7 b=8 b=9 based on checking out base systems 2 and 3
What is the similar mathematical operation that describes base-10 values to the left of the decimal?